#include<iostream>
using namespace std;
typedef long long LL;
const int N = 1e5 + 10;
int f[N];
int n;
LL fun(int x)
{
	LL ans = 0;
	for (int i = 1; i <= x / 2; i++) {
		ans += x / i;
	}
	if (x & 1)  ans += (x / 2) + 1;
	else ans += (x / 2);
	return ans;
}
int main()
{
	for (int i = 1; i < N; i++) {
		LL x = fun(i);
		f[i] = f[i - 1] + x;
		cout << "i==" << i << endl;
		cout << "f[i]==" << f[i] << endl;
	}
	return 0;
}